Bonjour si bien comprit votre demande voila le screener pour des détecter les twists ut jour h4 et h1
vous pouvez changer (depuis combien de bougies il a apparu ) en modifiant le chiffre par ut dans les variables nbs1 nbs2 et nbs3
//DETECTIN TWIST HAUSSIER
//----------------------------------------
total = 0
c1 = 0
TIMEFRAME(daily)
tenkan1 = ((highest[9](High)) + (lowest[9](Low)))/2
kijun1 = ((highest[26](High)) + (lowest[26](Low)))/2
s1 = (tenkan1 + kijun1) / 2
d1 = (highest[52](high) + lowest[52](Low)) /2
nbs1 = 1 // pour changer le nombres d bougies depuis le twist
TIMEFRAME(4 hours)
tenkan2 = ((highest[9](High)) + (lowest[9](Low)))/2
kijun2 = ((highest[26](High)) + (lowest[26](Low)))/2
s2 = (tenkan2 + kijun2) / 2
d2 = (highest[52](high) + lowest[52](Low)) /2
nbs2 = 1 // pour changer le nombres d bougies depuis le twist
TIMEFRAME(1 hours)
tenkan3 = ((highest[9](High)) + (lowest[9](Low)))/2
kijun3 = ((highest[26](High)) + (lowest[26](Low)))/2
s3 = (tenkan3 + kijun3) / 2
d3 = (highest[52](high) + lowest[52](Low)) /2
nbs3 = 1 // pour changer le nombres d bougies depuis le twist
//--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
// CONDITION TWIST JOUR
//--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
for i = 1 to nbs1
if s1[i] > d1[i] and s1[i+1] < d1[i+1] then
total = (i*10000)
break
endif
next
//--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
// CONDITION TWIST 4 heures
//--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
for i = 1 to nbs2
if s2[i] > d2[i] and s2[i+1] < d2[i+1] then
total = (i*100)
break
endif
next
//--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
// CONDITION TWIST 1 heurs
//--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
for i = 1 to nbs3
if s3[i] > d3[i] and s3[i+1] < d3[i+1] then
total = i
break
endif
next
//--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
c1 = total > 0
SCREENER[c1] (total AS "Roch ")




